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NEW QUESTION # 74
Which of the advantages listed below, makes an ice TES system more preferred over a water TES system, when a load shifting strategy is considered?
Answer: A
Explanation:
To determine which advantage makes an ice Thermal Energy Storage (TES) system more preferred over a water TES system for a load shifting strategy, we need to evaluate each option based on the principles of thermal energy storage as outlined in the Association of Energy Engineers (AEE) Certified EnergyManager (CEM) training materials. Load shifting involves storing energy (cooling capacity) during off-peak periods and releasing it during peak demand, making storage efficiency and capacity critical. Let's analyze each option step-by-step.
Step 1: Understand Ice TES vs. Water TES in Load Shifting
* Ice TES: Uses the latent heat of fusion of water (ice melting) to store cooling energy. Ice is formed during off-peak hours (e.g., overnight) and melted during peak hours to provide cooling.
* Water TES: Uses the sensible heat capacity of water, storing chilled water (typically 4-6°C) to provide cooling.
* Load Shifting Goal: Maximize cooling storage in minimal space and cost, shifting electrical demand from peak to off-peak periods.
* CEM Reference: CEM materials in the "Thermal Energy Storage" section highlight ice TES for its high energy density and compact storage, contrasted with water TES for simpler operation but larger volume requirements.
Step 2: Evaluate Each Option
Option A: Ice-storage systems operate with a higher coefficient of performance (COP)
* Analysis:
* COP Definition: COP = (Cooling Output) / (Energy Input). For TES, this relates to the chiller's efficiency.
* Ice TES: Requires chillers to operate at lower temperatures (e.g., -5°C to 0°C) to freeze water, which typically reduces chiller COP (e.g., 3-4) compared to water TES chillers operating at 4-6° C (COP ~5-6).
* Reality: Ice TES systems often have a lower COP due to the additional energy needed for phase change, though total system efficiency may improve with load shifting benefits.
* CEM Reference: CEM notes that ice TES energy input is higher per unit of cooling due to lower evaporating temperatures, contradicting a "higher COP" claim.
* Conclusion: This statement is incorrect and not an advantage for ice TES in load shifting.
Option B: Ice-storage systems require smaller storage tanks since ice has a higher energy storage density
* Analysis:
* Energy Storage Density:
* Ice TES: Relies on latent heat of fusion = 334 kJ/kg (80 kcal/kg or ~144 Btu/lb). This is the energy absorbed/released when water freezes/melts, far exceeding sensible heat.
* Water TES: Relies on sensible heat = cp##T c_p cdot Delta T cp##T, where cp=4.18 kJ
/kgcdotp°C c_p = 4.18 , text{kJ/kg °C} cp=4.18kJ/kgcdotp°C (1 Btu/lb °F). For a typical #T=10°CDelta T = 10°C#T=10°C (e.g., 4°C to 14°C), energy stored = 4.18×10=41.
8 kJ/kg 4.18 times 10 = 41.8 , text{kJ/kg} 4.18×10=41.8kJ/kg (~20 Btu/lb).
* Comparison: Ice stores ~8 times more energy per kg than water for a 10°C range (334 vs.
41.8 kJ/kg).
* Volume Impact: Ice's density (~917 kg/m³) is slightly less than water (~1000 kg/m³), but the latent heat advantage dominates, reducing required tank volume significantly.
* Load Shifting: Smaller tanks mean less space and potentially lower capital costs, a key advantage for peak load management.
* CEM Reference: CEM training emphasizes ice TES's high energy density as a primary reason for its preference in space-constrained load shifting applications.
* Conclusion: This statement is correct and a clear advantage for ice TES.
Option C: Water-storage systems require smaller storage tanks since water has a higher density than ice
* Analysis:
* Density: Water = 1000 kg/m³; Ice = 917 kg/m³. Water is denser, but density alone doesn't determine storage size in TES.
* Energy Storage: As calculated, water's sensible heat capacity (e.g., 41.8 kJ/kg for 10°C) is much lower than ice's latent heat (334 kJ/kg). To store the same cooling capacity, water TES requires
~8 times more mass and thus larger tanks (even accounting for density differences).
* Implication: Water TES tanks are larger, not smaller, contradicting the statement.
* CEM Reference: CEM materials note water TES's larger volume requirements as a disadvantage compared to ice TES.
* Conclusion: This statement is incorrect and not an advantage for ice TES (it favors water TES incorrectly).
Option D: Ice-storage systems require lower maintenance due to lower pumping volume
* Analysis:
* Pumping Volume: Ice TES often uses glycol or brine solutions to transfer heat at lower temperatures, requiring pumps sized for smaller volumes due to concentrated coolingcapacity.
Water TES circulates larger volumes of chilled water. However, "lower pumping volume" doesn' t directly translate to "lower maintenance."
* Maintenance: Ice TES systems are more complex (ice-making equipment, heat exchangers), potentially increasing maintenance (e.g., defrost cycles, corrosion from brine). Water TES is simpler, often with lower maintenance needs.
* CEM Reference: CEM discusses ice TES complexity as a trade-off for its density advantage, not a maintenance benefit.
* Conclusion: This statement is questionable and not a primary advantage for load shifting.
Step 3: Identify the Key Advantage for Load Shifting
* Load Shifting Context: The goal is to store maximum cooling capacity efficiently during off-peak hours. Option B (smaller tanks due to higher energy storage density) directly supports this by reducing space and installation costs, a critical factor in TES design per CEM guidelines.
* Elimination:
* A: Incorrect (lower COP, not higher).
* C: Incorrect (water TES tanks are larger).
* D: Weak (maintenance isn't clearly lower; not the primary driver).
* B: Correct and relevant.
NEW QUESTION # 75
A gas-fired boiler is operating with 31.9% excess air. A feedwater economizer is used to reduce the stack temperature rise from 310°C to 160°C. Using the natural gas combustion efficiency tables in your workbook, find the energy savings from the economizer as a percentage of historical fuel consumption.
Answer: A
NEW QUESTION # 76
How much energy (kJ) is required to heat 2 kg of water from 25°C to 2 kg of water at 100°C? (The specific heat of water (C) is 4.2 kJ/kg-°C. Assume no system losses.)
Answer: D
NEW QUESTION # 77
A piece of equipment costs $250,000 to buy and install. The annual operating cost for the equipment is
$50,000 per year. The equipment will last 15 years. After 15 years, the equipment will have no net salvage value. The annual interest rate is 10%. What is the present value of the life-cycle cost to own and operate the equipment? Use end-of-year annual cash flow analysis.
Answer: B
NEW QUESTION # 78
If outside air has a temperature of 30°C dry bulb and 20°C wet bulb, what is the dew point temperature?
Answer: B
NEW QUESTION # 79
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